What are the solutions to the equation -x^2+14x-49=0 ?

The solutions to the equation -x^2+14x-49=0 are x=7

Find the zeros of -x^2+14x-49=0

The zeros of -x^2+14x-49=0 are x=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 14 x - 49 = 0

x = 7

Solution steps

- x^{2} + 14 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 1 ) ( - 49 )}{2 ( - 1 )}

1 4^{2} - 4 (- 1) (- 49) = 0

x_{1, 2} = \frac{- 14 \pm 0}{2 ( - 1 )}

x = \frac{- 14}{2 ( - 1 )}

\frac{- 14}{2 ( - 1 )} = 7

x = 7

The solution to the quadratic equation is:

x = 7

lo g_{\frac{1}{4}} (64) = n

49 - 4 z^{2}

(4 + \frac{1}{2})^{2}

\frac{3}{10} m - \frac{2}{5} = \frac{1}{10}

e^{\frac{1}{x - 1} - \frac{1}{x}} \leq 0

What are the solutions to the equation -x^2+14x-49=0 ?
The solutions to the equation -x^2+14x-49=0 are x=7
Find the zeros of -x^2+14x-49=0
The zeros of -x^2+14x-49=0 are x=7