What are the solutions to the equation x^2-16x+64=0 ?

The solutions to the equation x^2-16x+64=0 are x=8

Find the zeros of x^2-16x+64=0

The zeros of x^2-16x+64=0 are x=8

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x^{2} - 16 x + 64 = 0

x = 8

Solution steps

x^{2} - 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

x = 8

The solution to the quadratic equation is:

x = 8

x^{2} = - 1

6 n^{2} + 6 n

x^{- \frac{1}{5}}

- 1 d > 3

x < 3 ∣ 1 - x ∣ - 2 ∣ x - 2 ∣

What are the solutions to the equation x^2-16x+64=0 ?
The solutions to the equation x^2-16x+64=0 are x=8
Find the zeros of x^2-16x+64=0
The zeros of x^2-16x+64=0 are x=8