What are the solutions to the equation 3x^2-27x=-5x-7 ?

The solutions to the equation 3x^2-27x=-5x-7 are x=7,x= 1/3

Find the zeros of 3x^2-27x=-5x-7

The zeros of 3x^2-27x=-5x-7 are x=7,x= 1/3

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3 x^{2} - 27 x = - 5 x - 7

x = 7, x = \frac{1}{3}

Solution steps

3 x^{2} - 27 x = - 5 x - 7

Move

7

to the left side

3 x^{2} - 27 x + 7 = - 5 x

Move

5 x

to the left side

3 x^{2} - 22 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

(- 22)^{2} - 4 \cdot 3 \cdot 7 = 20

x_{1, 2} = \frac{- ( - 22 ) \pm 20}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 20}{2 \cdot 3}, x_{2} = \frac{- ( - 22 ) - 20}{2 \cdot 3}

x = \frac{- ( - 22 ) + 20}{2 \cdot 3} : 7

x = \frac{- ( - 22 ) - 20}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 7, x = \frac{1}{3}

36 a^{4} - 4 a^{2}

1^{0.1}

\frac{7}{27 m ^{2} n} - \frac{8}{18 m ^{4} n ^{6}}

h^{2} - 14 h + 13

\frac{14 - 18}{2.4 - 2.8}

What are the solutions to the equation 3x^2-27x=-5x-7 ?
The solutions to the equation 3x^2-27x=-5x-7 are x=7,x= 1/3
Find the zeros of 3x^2-27x=-5x-7
The zeros of 3x^2-27x=-5x-7 are x=7,x= 1/3