What is -2(2-x)<= (x+2)(x-2)<= 2(2-x) ?

The solution to -2(2-x)<= (x+2)(x-2)<= 2(2-x) is -4<= x<= 0\lor x=2

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-2(2-x)<= (x+2)(x-2)<= 2(2-x)

- 2 (2 - x) \leq (x + 2) (x - 2) \leq 2 (2 - x)

- 4 \leq x \leq 0 or x = 2

Interval Notation

[- 4, 0] \cup x = 2

Solution steps

- 2 (2 - x) \leq (x + 2) (x - 2) \leq 2 (2 - x)

a \leq u \leq b

then

a \leq u and u \leq b

- 2 (2 - x) \leq (x + 2) (x - 2) and (x + 2) (x - 2) \leq 2 (2 - x)

- 2 (2 - x) \leq (x + 2) (x - 2) : x \leq 0 or x \geq 2

(x + 2) (x - 2) \leq 2 (2 - x) : - 4 \leq x \leq 2

Combine the intervals

(x \leq 0 or x \geq 2) and - 4 \leq x \leq 2

Merge Overlapping Intervals

- 4 \leq x \leq 0 or x = 2

\frac{24 + 5 n - n ^{2}}{n ^{2} - 16 n + 64}

5^{2} \cdot 5^{5}

8 x - 6 y x^{2} + 1

x^{2} - 4 \geq 1

8 x^{2} - 10 = - 2

What is -2(2-x)<= (x+2)(x-2)<= 2(2-x) ?
The solution to -2(2-x)<= (x+2)(x-2)<= 2(2-x) is -4<= x<= 0\lor x=2