What is the answer to 2x(x-8)=(x+1)(2x-3) ?

The answer to 2x(x-8)=(x+1)(2x-3) is x= 1/5

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2x(x-8)=(x+1)(2x-3)

2 x (x - 8) = (x + 1) (2 x - 3)

x = \frac{1}{5}

Solution steps

2 x (x - 8) = (x + 1) (2 x - 3)

Expand

2 x (x - 8) : 2 x^{2} - 16 x

Expand

(x + 1) (2 x - 3) : 2 x^{2} - x - 3

2 x^{2} - 16 x = 2 x^{2} - x - 3

Subtract

2 x^{2} - x

from both sides

2 x^{2} - 16 x - (2 x^{2} - x) = 2 x^{2} - x - 3 - (2 x^{2} - x)

Simplify

- 15 x = - 3

Divide both sides by

- 15

x = \frac{1}{5}

(2 x)^{4}

(0.6)^{2}

\frac{3 + 2 i}{6 + 5 i}

25 0^{2}

What is the answer to 2x(x-8)=(x+1)(2x-3) ?
The answer to 2x(x-8)=(x+1)(2x-3) is x= 1/5
Solve for x: 2x(x-8)=(x+1)(2x-3)
The solution is x= 1/5