What are the solutions to the equation 224t-16t^2=0 ?

The solutions to the equation 224t-16t^2=0 are t=0,t=14

Find the zeros of 224t-16t^2=0

The zeros of 224t-16t^2=0 are t=0,t=14

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224 t - 16 t^{2} = 0

t = 0, t = 14

Solution steps

224 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 224 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 224 \pm 22 4 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

22 4^{2} - 4 (- 16) \cdot 0 = 224

t_{1, 2} = \frac{- 224 \pm 224}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 224 + 224}{2 ( - 16 )}, t_{2} = \frac{- 224 - 224}{2 ( - 16 )}

t = \frac{- 224 + 224}{2 ( - 16 )} : 0

t = \frac{- 224 - 224}{2 ( - 16 )} : 14

The solutions to the quadratic equation are:

t = 0, t = 14

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2 c + 10 \geq 4

\frac{x ^{- 2} y ^{\frac{1}{2}}}{x ^{\frac{1}{3}} y ^{- 1}}

0 \leq 3 x - 4 \leq 8

What are the solutions to the equation 224t-16t^2=0 ?
The solutions to the equation 224t-16t^2=0 are t=0,t=14
Find the zeros of 224t-16t^2=0
The zeros of 224t-16t^2=0 are t=0,t=14