What are the solutions to the equation x^2-10x+49=4x+1 ?

The solutions to the equation x^2-10x+49=4x+1 are x=8,x=6

Find the zeros of x^2-10x+49=4x+1

The zeros of x^2-10x+49=4x+1 are x=8,x=6

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x^{2} - 10 x + 49 = 4 x + 1

x = 8, x = 6

Solution steps

x^{2} - 10 x + 49 = 4 x + 1

Move

1

to the left side

x^{2} - 10 x + 48 = 4 x

Move

4 x

to the left side

x^{2} - 14 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 48}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 48 = 2

x_{1, 2} = \frac{- ( - 14 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2}{2 \cdot 1} : 8

x = \frac{- ( - 14 ) - 2}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 8, x = 6

\frac{1}{2} + \frac{3}{7}

\frac{8 k}{9 k - 4} - \frac{3 k ^{3}}{2 k + 7}

5 x^{2} - 3 x + 2 = 0

1.5 \times 1 0^{- 5}

f = 2^{- 1}

What are the solutions to the equation x^2-10x+49=4x+1 ?
The solutions to the equation x^2-10x+49=4x+1 are x=8,x=6
Find the zeros of x^2-10x+49=4x+1
The zeros of x^2-10x+49=4x+1 are x=8,x=6