What are the solutions to the equation j^2=25 ?

The solutions to the equation j^2=25 are j=5,j=-5

Find the zeros of j^2=25

The zeros of j^2=25 are j=5,j=-5

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j^{2} = 25

j = 5, j = - 5

Solution steps

j^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

j = 25, j = - 25

25 = 5

- 25 = - 5

j = 5, j = - 5

\frac{x + 1}{2} = - 7

6 m^{2} + 4 m - 9 mn - 6 n

4 - x \geq 3 x + 4

- 8 \geq \frac{u}{2}

9 x^{2} - 6 y

What are the solutions to the equation j^2=25 ?
The solutions to the equation j^2=25 are j=5,j=-5
Find the zeros of j^2=25
The zeros of j^2=25 are j=5,j=-5