What are the solutions to the equation x^2+5=1 ?

The solutions to the equation x^2+5=1 are x=2i,x=-2i

Find the zeros of x^2+5=1

The zeros of x^2+5=1 are x=2i,x=-2i

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x^{2} + 5 = 1

x = 2 i, x = - 2 i

Solution steps

x^{2} + 5 = 1

Move

5

to the right side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

\frac{2 x}{5} - x = \frac{x}{10} - \frac{35}{2}

2 x^{2} - 4 x - 48 = 0

- \frac{2}{3} - \frac{2}{5}

x^{4} + 6 x^{2} - 27

\frac{w}{- 5} \geq 9

What are the solutions to the equation x^2+5=1 ?
The solutions to the equation x^2+5=1 are x=2i,x=-2i
Find the zeros of x^2+5=1
The zeros of x^2+5=1 are x=2i,x=-2i