What is (11b^2-4b+7)-(b^2+8b-9) ?

The solution to (11b^2-4b+7)-(b^2+8b-9) is 10b^2-12b+16

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simplify (11b^2-4b+7)-(b^2+8b-9)

simplify

(11 b^{2} - 4 b + 7) - (b^{2} + 8 b - 9)

10 b^{2} - 12 b + 16

Solution steps

(11 b^{2} - 4 b + 7) - (b^{2} + 8 b - 9)

Apply rule:

(a) = a

(11 b^{2} - 4 b + 7) = 11 b^{2} - 4 b + 7

= 11 b^{2} - 4 b + 7 - (b^{2} + 8 b - 9)

Apply the distributive law:

- (a + b) = - a - b

- (b^{2} + 8 b - 9) = - b^{2} - 8 b + 9

= 11 b^{2} - 4 b + 7 - b^{2} - 8 b + 9

Group like terms

= 11 b^{2} - b^{2} - 4 b - 8 b + 7 + 9

Add similar elements:

11 b^{2} - b^{2} = 10 b^{2}

= 10 b^{2} - 4 b - 8 b + 7 + 9

Add similar elements:

- 4 b - 8 b = - 12 b

= 10 b^{2} - 12 b + 7 + 9

Add the numbers:

7 + 9 = 16

= 10 b^{2} - 12 b + 16

8 b^{2} - 10 b + 3 = 0

- 1 - 2 x > - 1

(x - 1)^{2}

20 \geq 2 c + 4

2 \cdot lo g_{3} (8) - 4 \cdot lo g_{3} (2)

What is (11b^2-4b+7)-(b^2+8b-9) ?
The solution to (11b^2-4b+7)-(b^2+8b-9) is 10b^2-12b+16