What are the solutions to the equation x^2-5x+2=0 ?

The solutions to the equation x^2-5x+2=0 are x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2

Find the zeros of x^2-5x+2=0

The zeros of x^2-5x+2=0 are x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2

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x^{2} - 5 x + 2 = 0

x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

Solution steps

x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 2 = 17

x_{1, 2} = \frac{- ( - 5 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 17}{2 \cdot 1}

x = \frac{- ( - 5 ) + 17}{2 \cdot 1} : \frac{5 + 17}{2}

x = \frac{- ( - 5 ) - 17}{2 \cdot 1} : \frac{5 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

x^{2} - 3 x = 28

4 y - 2 < 7 y - 14

(\frac{1}{4} + \frac{1}{7} i) - (\frac{5}{6} + \frac{7}{2} i)

x ln (x) - x > 0

(2 x + 3) 2 - 14 x - 21 = - 6

What are the solutions to the equation x^2-5x+2=0 ?
The solutions to the equation x^2-5x+2=0 are x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2
Find the zeros of x^2-5x+2=0
The zeros of x^2-5x+2=0 are x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2