What are the solutions to the equation m^2+2m+1=0 ?

The solutions to the equation m^2+2m+1=0 are m=-1

Find the zeros of m^2+2m+1=0

The zeros of m^2+2m+1=0 are m=-1

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m^{2} + 2 m + 1 = 0

m = - 1

Solution steps

m^{2} + 2 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

m_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

m = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

m = - 1

The solution to the quadratic equation is:

m = - 1

\frac{1}{2} (t - 6) \leq 22

1 1^{- 1}

q^{2} = 2 q + 4

x^{2} + 8 x - 65

- \frac{1}{3} \cdot (- \frac{1}{3})

What are the solutions to the equation m^2+2m+1=0 ?
The solutions to the equation m^2+2m+1=0 are m=-1
Find the zeros of m^2+2m+1=0
The zeros of m^2+2m+1=0 are m=-1