What are the solutions to the equation x^2-24x-144=0 ?

The solutions to the equation x^2-24x-144=0 are x=12(1+sqrt(2)),x=12(1-sqrt(2))

Find the zeros of x^2-24x-144=0

The zeros of x^2-24x-144=0 are x=12(1+sqrt(2)),x=12(1-sqrt(2))

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x^{2} - 24 x - 144 = 0

x = 12 (1 + 2), x = 12 (1 - 2)

Decimal Notation

x = 28.97056 \dots, x = - 4.97056 \dots

Solution steps

x^{2} - 24 x - 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot ( - 144 )}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot (- 144) = 242

x_{1, 2} = \frac{- ( - 24 ) \pm 24 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 24 2}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 24 2}{2 \cdot 1}

x = \frac{- ( - 24 ) + 24 2}{2 \cdot 1} : 12 (1 + 2)

x = \frac{- ( - 24 ) - 24 2}{2 \cdot 1} : 12 (1 - 2)

The solutions to the quadratic equation are:

x = 12 (1 + 2), x = 12 (1 - 2)

∣ 3 - x ∣ \leq 5

(- 1331)^{- \frac{2}{3}}

\frac{( 2 x + 5 )}{x ^{2} + 2 x - 35} \geq 0

\frac{a ^{m}}{a ^{n}}

9 = - x^{2} - 6 x

What are the solutions to the equation x^2-24x-144=0 ?
The solutions to the equation x^2-24x-144=0 are x=12(1+sqrt(2)),x=12(1-sqrt(2))
Find the zeros of x^2-24x-144=0
The zeros of x^2-24x-144=0 are x=12(1+sqrt(2)),x=12(1-sqrt(2))