What are the solutions to the equation -x^2+10x-25=0 ?

The solutions to the equation -x^2+10x-25=0 are x=5

Find the zeros of -x^2+10x-25=0

The zeros of -x^2+10x-25=0 are x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 10 x - 25 = 0

x = 5

Solution steps

- x^{2} + 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 25) = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 ( - 1 )}

x = \frac{- 10}{2 ( - 1 )}

\frac{- 10}{2 ( - 1 )} = 5

x = 5

The solution to the quadratic equation is:

x = 5

\frac{( - 6 a ^{5} b ) ^{2}}{12 a ^{7} b} - 8 a^{3} b

\frac{2}{∣ 2 x - 3 ∣} \geq 3

- 10 x + 9 \leq - 9 (x - 1)

2 x - 10 \geq 8

(x + 1)^{2} (x - 1)^{2}

What are the solutions to the equation -x^2+10x-25=0 ?
The solutions to the equation -x^2+10x-25=0 are x=5
Find the zeros of -x^2+10x-25=0
The zeros of -x^2+10x-25=0 are x=5