What are the solutions to the equation 10+3y-y^2=0 ?

The solutions to the equation 10+3y-y^2=0 are y=-2,y=5

Find the zeros of 10+3y-y^2=0

The zeros of 10+3y-y^2=0 are y=-2,y=5

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10 + 3 y - y^{2} = 0

y = - 2, y = 5

Solution steps

10 + 3 y - y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- y^{2} + 3 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 10 = 7

y_{1, 2} = \frac{- 3 \pm 7}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- 3 + 7}{2 ( - 1 )}, y_{2} = \frac{- 3 - 7}{2 ( - 1 )}

y = \frac{- 3 + 7}{2 ( - 1 )} : - 2

y = \frac{- 3 - 7}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

y = - 2, y = 5

s^{2} \leq 3

- 8 (35 x + 40) = - 16 (1 + 17 x) + 11 x

24 x^{3} - 36 x^{2} + 72 x - 108

5 x + 10 = 4 x + 23

- 4 - \frac{3}{8} x < 26

What are the solutions to the equation 10+3y-y^2=0 ?
The solutions to the equation 10+3y-y^2=0 are y=-2,y=5
Find the zeros of 10+3y-y^2=0
The zeros of 10+3y-y^2=0 are y=-2,y=5