What is factor 6(a+b)^2+17(a+b)+5 ?

The solution to factor 6(a+b)^2+17(a+b)+5 is (3(a+b)+1)(2(a+b)+5)

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factor 6(a+b)^2+17(a+b)+5

factor

6 (a + b)^{2} + 17 (a + b) + 5

(3 (a + b) + 1) (2 (a + b) + 5)

Solution steps

6 (a + b)^{2} + 17 (a + b) + 5

Break the expression into groups

= (6 (a + b)^{2} + 2 (a + b)) + (15 (a + b) + 5)

Factor out

2 (a + b)

from

6 (a + b)^{2} + 2 (a + b) : 2 (a + b) (3 (a + b) + 1)

Factor out

5

from

15 (a + b) + 5 : 5 (3 (a + b) + 1)

= 2 (a + b) (3 (a + b) + 1) + 5 (3 (a + b) + 1)

Factor out common term

3 (a + b) + 1

= (3 (a + b) + 1) (2 (a + b) + 5)

2 < 0

- (- 1)^{3}

3 a + 4 {c - 2 a [3 (4 - b)] + 3 c} + 3

4 + \frac{x}{3} = 26

x^{2} - 14 x + 49 = 1

What is factor 6(a+b)^2+17(a+b)+5 ?
The solution to factor 6(a+b)^2+17(a+b)+5 is (3(a+b)+1)(2(a+b)+5)