What are the solutions to the equation -x^2+9x=18 ?

The solutions to the equation -x^2+9x=18 are x=3,x=6

Find the zeros of -x^2+9x=18

The zeros of -x^2+9x=18 are x=3,x=6

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- x^{2} + 9 x = 18

x = 3, x = 6

Solution steps

- x^{2} + 9 x = 18

Move

18

to the left side

- x^{2} + 9 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) ( - 18 )}{2 ( - 1 )}

9^{2} - 4 (- 1) (- 18) = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 ( - 1 )}, x_{2} = \frac{- 9 - 3}{2 ( - 1 )}

x = \frac{- 9 + 3}{2 ( - 1 )} : 3

x = \frac{- 9 - 3}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 3, x = 6

y + 5.4 = - 0.7

8 x^{2} - 10 x = 0

13 = 5 - 8 m

5 (y + 1) - y = 4 (y - 1) + 9

X^{2} - \frac{9}{16} = 0

What are the solutions to the equation -x^2+9x=18 ?
The solutions to the equation -x^2+9x=18 are x=3,x=6
Find the zeros of -x^2+9x=18
The zeros of -x^2+9x=18 are x=3,x=6