What are the solutions to the equation 3x^2-12x+11=0 ?

The solutions to the equation 3x^2-12x+11=0 are x=(6+sqrt(3))/3 ,x=(6-sqrt(3))/3

Find the zeros of 3x^2-12x+11=0

The zeros of 3x^2-12x+11=0 are x=(6+sqrt(3))/3 ,x=(6-sqrt(3))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 12 x + 11 = 0

x = \frac{6 + 3}{3}, x = \frac{6 - 3}{3}

Decimal Notation

x = 2.57735 \dots, x = 1.42264 \dots

Solution steps

3 x^{2} - 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 11}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 11 = 23

x_{1, 2} = \frac{- ( - 12 ) \pm 2 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 3}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 2 3}{2 \cdot 3}

x = \frac{- ( - 12 ) + 2 3}{2 \cdot 3} : \frac{6 + 3}{3}

x = \frac{- ( - 12 ) - 2 3}{2 \cdot 3} : \frac{6 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{6 + 3}{3}, x = \frac{6 - 3}{3}

\frac{x}{19} = 4

- 88 = 11 r

385

\frac{5}{8} + \frac{1}{4} + \frac{7}{12}

\frac{5 x - 2}{- 4} = - 7

What are the solutions to the equation 3x^2-12x+11=0 ?
The solutions to the equation 3x^2-12x+11=0 are x=(6+sqrt(3))/3 ,x=(6-sqrt(3))/3
Find the zeros of 3x^2-12x+11=0
The zeros of 3x^2-12x+11=0 are x=(6+sqrt(3))/3 ,x=(6-sqrt(3))/3