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Popular >

(x^2-1)/(x+3)<= 0

Solution

\frac{x ^{2} - 1}{x + 3} \leq 0

Solution

x < - 3 or - 1 \leq x \leq 1

+1

Interval Notation

(- \infty, - 3) \cup [- 1, 1]

Solution steps

\frac{x ^{2} - 1}{x + 3} \leq 0

Factor

\frac{x ^{2} - 1}{x + 3} : \frac{( x + 1 ) ( x - 1 )}{x + 3}

\frac{( x + 1 ) ( x - 1 )}{x + 3} \leq 0

Identify the intervals

x < - 3 or - 1 \leq x \leq 1

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Frequently Asked Questions (FAQ)

What is (x^2-1)/(x+3)<= 0 ?
The solution to (x^2-1)/(x+3)<= 0 is x<-3\lor-1<= x<= 1