What are the solutions to the equation 2b^2-b-7=14 ?

The solutions to the equation 2b^2-b-7=14 are b= 7/2 ,b=-3

Find the zeros of 2b^2-b-7=14

The zeros of 2b^2-b-7=14 are b= 7/2 ,b=-3

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2 b^{2} - b - 7 = 14

b = \frac{7}{2}, b = - 3

Decimal Notation

b = 3.5, b = - 3

Solution steps

2 b^{2} - b - 7 = 14

Move

14

to the left side

2 b^{2} - b - 21 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 21) = 13

b_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 2}

Separate the solutions

b_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 2}, b_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 2}

b = \frac{- ( - 1 ) + 13}{2 \cdot 2} : \frac{7}{2}

b = \frac{- ( - 1 ) - 13}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

b = \frac{7}{2}, b = - 3

2 + 3 t = 1 + t^{2}

\frac{e ^{\frac{c}{m} t}}{e ^{\frac{c}{m} t}}

\frac{3 - 2 i}{2 - 3 i}

3 x - 1 = - 2 x + 39

27 x^{2} + 72 x y + 48 y^{2}

What are the solutions to the equation 2b^2-b-7=14 ?
The solutions to the equation 2b^2-b-7=14 are b= 7/2 ,b=-3
Find the zeros of 2b^2-b-7=14
The zeros of 2b^2-b-7=14 are b= 7/2 ,b=-3