What are the solutions to the equation 25p^2-40p+16=0 ?

The solutions to the equation 25p^2-40p+16=0 are p= 4/5

Find the zeros of 25p^2-40p+16=0

The zeros of 25p^2-40p+16=0 are p= 4/5

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25 p^{2} - 40 p + 16 = 0

p = \frac{4}{5}

Decimal Notation

p = 0.8

Solution steps

25 p^{2} - 40 p + 16 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

p_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

p = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

p = \frac{4}{5}

The solution to the quadratic equation is:

p = \frac{4}{5}

x + 2 = x + 4

k^{2} - 16 h^{2}

(e^{x} - e^{- x})^{2}

b^{- \frac{2}{3}}

What are the solutions to the equation 25p^2-40p+16=0 ?
The solutions to the equation 25p^2-40p+16=0 are p= 4/5
Find the zeros of 25p^2-40p+16=0
The zeros of 25p^2-40p+16=0 are p= 4/5