What are the solutions to the equation 5x^2-12x+3=0 ?

The solutions to the equation 5x^2-12x+3=0 are x=(6+sqrt(21))/5 ,x=(6-sqrt(21))/5

Find the zeros of 5x^2-12x+3=0

The zeros of 5x^2-12x+3=0 are x=(6+sqrt(21))/5 ,x=(6-sqrt(21))/5

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5 x^{2} - 12 x + 3 = 0

x = \frac{6 + 21}{5}, x = \frac{6 - 21}{5}

Decimal Notation

x = 2.11651 \dots, x = 0.28348 \dots

Solution steps

5 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 \cdot 3 = 221

x_{1, 2} = \frac{- ( - 12 ) \pm 2 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 21}{2 \cdot 5}, x_{2} = \frac{- ( - 12 ) - 2 21}{2 \cdot 5}

x = \frac{- ( - 12 ) + 2 21}{2 \cdot 5} : \frac{6 + 21}{5}

x = \frac{- ( - 12 ) - 2 21}{2 \cdot 5} : \frac{6 - 21}{5}

The solutions to the quadratic equation are:

x = \frac{6 + 21}{5}, x = \frac{6 - 21}{5}

6 - \frac{1}{4} r > 3 - r

3 (u + 2) + u = 4 (u - 1) + 9

36 \cdot 9

t - \frac{3}{5} = \frac{4}{5}

(3 x - 7)^{2} - 5 (2 x + 1) (x - 2) = - x - (- (3 x + 1))

What are the solutions to the equation 5x^2-12x+3=0 ?
The solutions to the equation 5x^2-12x+3=0 are x=(6+sqrt(21))/5 ,x=(6-sqrt(21))/5
Find the zeros of 5x^2-12x+3=0
The zeros of 5x^2-12x+3=0 are x=(6+sqrt(21))/5 ,x=(6-sqrt(21))/5