What is ((2x^3z^2)^3)/(x^3y^4z^2*x^{-4)z^3} ?

The solution to ((2x^3z^2)^3)/(x^3y^4z^2*x^{-4)z^3} is (8x^{10}z)/(y^4)

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simplify ((2x^3z^2)^3)/(x^3y^4z^2*x^{-4)z^3}

simplify

\frac{( 2 x ^{3} z ^{2} ) ^{3}}{x ^{3} y ^{4} z ^{2} \cdot x ^{- 4} z ^{3}}

\frac{8 x ^{10} z}{y ^{4}}

Solution steps

\frac{( 2 x ^{3} z ^{2} ) ^{3}}{x ^{3} y ^{4} z ^{2} x ^{- 4} z ^{3}}

Simplify

(2 x^{3} z^{2})^{3} : 8 x^{9} z^{6}

= \frac{8 x ^{9} z ^{6}}{x ^{3} y ^{4} z ^{2} x ^{- 4} z ^{3}}

Simplify

\frac{x ^{9}}{x ^{3}} : x^{6}

= \frac{8 x ^{6} z ^{6}}{y ^{4} z ^{2} x ^{- 4} z ^{3}}

Simplify

\frac{x ^{6}}{x ^{- 4}} : x^{10}

= \frac{8 x ^{10} z ^{6}}{y ^{4} z ^{2} z ^{3}}

Simplify

\frac{z ^{6}}{z ^{2}} : z^{4}

= \frac{8 x ^{10} z ^{4}}{y ^{4} z ^{3}}

Simplify

\frac{z ^{4}}{z ^{3}} : z

= \frac{8 x ^{10} z}{y ^{4}}

- 9 m - 27

x + \frac{3}{8} = - \frac{1}{4}

9 x^{2} + 24 x + 32 = 0

4 x^{2} - 36 x y + 81 y^{2}

\frac{15 x ^{6} y}{25 x ^{2} y ^{4}}

What is ((2x^3z^2)^3)/(x^3y^4z^2*x^{-4)z^3} ?
The solution to ((2x^3z^2)^3)/(x^3y^4z^2*x^{-4)z^3} is (8x^{10}z)/(y^4)