What are the solutions to the equation 12^2+14^2=x^2 ?

The solutions to the equation 12^2+14^2=x^2 are x=2sqrt(85),x=-2sqrt(85)

Find the zeros of 12^2+14^2=x^2

The zeros of 12^2+14^2=x^2 are x=2sqrt(85),x=-2sqrt(85)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 2^{2} + 1 4^{2} = x^{2}

x = 285, x = - 285

Decimal Notation

x = 18.43908 \dots, x = - 18.43908 \dots

Solution steps

1 2^{2} + 1 4^{2} = x^{2}

Switch sides

x^{2} = 1 2^{2} + 1 4^{2}

Simplify

1 2^{2} + 1 4^{2} : 340

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 340, x = - 340

340 = 285

- 340 = - 285

x = 285, x = - 285

∣ 3 x - 1 ∣ > 14

3 x^{2} - 7 x < 2 x^{2} + 8

\frac{15 w}{4} - 10 = 9

81 x^{8} - 16 y^{8}

3 x^{2} + 5 x + 4 = 0

What are the solutions to the equation 12^2+14^2=x^2 ?
The solutions to the equation 12^2+14^2=x^2 are x=2sqrt(85),x=-2sqrt(85)
Find the zeros of 12^2+14^2=x^2
The zeros of 12^2+14^2=x^2 are x=2sqrt(85),x=-2sqrt(85)