What are the solutions to the equation 5x^2-4x+3=0 ?

The solutions to the equation 5x^2-4x+3=0 are x= 2/5+i(sqrt(11))/5 ,x= 2/5-i(sqrt(11))/5

Find the zeros of 5x^2-4x+3=0

The zeros of 5x^2-4x+3=0 are x= 2/5+i(sqrt(11))/5 ,x= 2/5-i(sqrt(11))/5

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5 x^{2} - 4 x + 3 = 0

x = \frac{2}{5} + i \frac{11}{5}, x = \frac{2}{5} - i \frac{11}{5}

Solution steps

5 x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

Simplify

(- 4)^{2} - 4 \cdot 5 \cdot 3 : 211 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 11 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 5}

x = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 5} : \frac{2}{5} + i \frac{11}{5}

x = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 5} : \frac{2}{5} - i \frac{11}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5} + i \frac{11}{5}, x = \frac{2}{5} - i \frac{11}{5}

(3 g^{4} + 5 g^{2} h + 1) - (3 g^{4} - 5 g^{2} + 8 h)

\frac{( x - 1 ) ( x + 2 )}{( x - 3 )} \geq 0

c^{3} + 8 d^{3}

- \frac{9}{4} v + \frac{4}{5} = \frac{7}{8}

What are the solutions to the equation 5x^2-4x+3=0 ?
The solutions to the equation 5x^2-4x+3=0 are x= 2/5+i(sqrt(11))/5 ,x= 2/5-i(sqrt(11))/5
Find the zeros of 5x^2-4x+3=0
The zeros of 5x^2-4x+3=0 are x= 2/5+i(sqrt(11))/5 ,x= 2/5-i(sqrt(11))/5