What are the solutions to the equation 3(x+5)^2=21 ?

The solutions to the equation 3(x+5)^2=21 are x=sqrt(7)-5,x=-sqrt(7)-5

Find the zeros of 3(x+5)^2=21

The zeros of 3(x+5)^2=21 are x=sqrt(7)-5,x=-sqrt(7)-5

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3 (x + 5)^{2} = 21

x = 7 - 5, x = - 7 - 5

Decimal Notation

x = - 2.35424 \dots, x = - 7.64575 \dots

Solution steps

3 (x + 5)^{2} = 21

Divide both sides by

3

(x + 5)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 7 : x = 7 - 5

Solve

x + 5 = - 7 : x = - 7 - 5

The solutions to the quadratic equation are:

x = 7 - 5, x = - 7 - 5

\frac{x + 12}{x + 2} \geq 3

4 y^{2} - 16 (- 4)^{2} = 64

3. 2^{1.5}

- 2 + \frac{1}{2}

r^{2} - 15 r + 54 = 0

What are the solutions to the equation 3(x+5)^2=21 ?
The solutions to the equation 3(x+5)^2=21 are x=sqrt(7)-5,x=-sqrt(7)-5
Find the zeros of 3(x+5)^2=21
The zeros of 3(x+5)^2=21 are x=sqrt(7)-5,x=-sqrt(7)-5