What are the solutions to the equation 2(x-2)^2=16 ?

The solutions to the equation 2(x-2)^2=16 are x=2sqrt(2)+2,x=-2sqrt(2)+2

Find the zeros of 2(x-2)^2=16

The zeros of 2(x-2)^2=16 are x=2sqrt(2)+2,x=-2sqrt(2)+2

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2 (x - 2)^{2} = 16

x = 22 + 2, x = - 22 + 2

Decimal Notation

x = 4.82842 \dots, x = - 0.82842 \dots

Solution steps

2 (x - 2)^{2} = 16

Divide both sides by

2

(x - 2)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 8 : x = 22 + 2

Solve

x - 2 = - 8 : x = - 22 + 2

The solutions to the quadratic equation are:

x = 22 + 2, x = - 22 + 2

\frac{1}{2} + \frac{2}{1}

2 (2 u - 7) = 22

5 (x + 7)^{2} = 245

12 x^{2} - 64

25 x^{12} - 36 y^{14}

What are the solutions to the equation 2(x-2)^2=16 ?
The solutions to the equation 2(x-2)^2=16 are x=2sqrt(2)+2,x=-2sqrt(2)+2
Find the zeros of 2(x-2)^2=16
The zeros of 2(x-2)^2=16 are x=2sqrt(2)+2,x=-2sqrt(2)+2