What are the solutions to the equation 3x^2-5x+7=0 ?

The solutions to the equation 3x^2-5x+7=0 are x= 5/6+i(sqrt(59))/6 ,x= 5/6-i(sqrt(59))/6

Find the zeros of 3x^2-5x+7=0

The zeros of 3x^2-5x+7=0 are x= 5/6+i(sqrt(59))/6 ,x= 5/6-i(sqrt(59))/6

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3 x^{2} - 5 x + 7 = 0

x = \frac{5}{6} + i \frac{59}{6}, x = \frac{5}{6} - i \frac{59}{6}

Solution steps

3 x^{2} - 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

(- 5)^{2} - 4 \cdot 3 \cdot 7 : 59 i

x_{1, 2} = \frac{- ( - 5 ) \pm 59 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 59 i}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 59 i}{2 \cdot 3}

x = \frac{- ( - 5 ) + 59 i}{2 \cdot 3} : \frac{5}{6} + i \frac{59}{6}

x = \frac{- ( - 5 ) - 59 i}{2 \cdot 3} : \frac{5}{6} - i \frac{59}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6} + i \frac{59}{6}, x = \frac{5}{6} - i \frac{59}{6}

9 w^{2} - 48 w x + 64 x^{2}

3 x + 4 = 9 x - 8

2 x^{2} + 8 x = - 1

3 x^{2} - 19 x y + 20 y^{2}

\frac{5 - 4 2}{4 - 3 2}

What are the solutions to the equation 3x^2-5x+7=0 ?
The solutions to the equation 3x^2-5x+7=0 are x= 5/6+i(sqrt(59))/6 ,x= 5/6-i(sqrt(59))/6
Find the zeros of 3x^2-5x+7=0
The zeros of 3x^2-5x+7=0 are x= 5/6+i(sqrt(59))/6 ,x= 5/6-i(sqrt(59))/6