What are the solutions to the equation 8x^2-35x+38=0 ?

The solutions to the equation 8x^2-35x+38=0 are x= 19/8 ,x=2

Find the zeros of 8x^2-35x+38=0

The zeros of 8x^2-35x+38=0 are x= 19/8 ,x=2

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8 x^{2} - 35 x + 38 = 0

x = \frac{19}{8}, x = 2

Decimal Notation

x = 2.375, x = 2

Solution steps

8 x^{2} - 35 x + 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 35 ) \pm ( - 35 ) ^{2} - 4 \cdot 8 \cdot 38}{2 \cdot 8}

(- 35)^{2} - 4 \cdot 8 \cdot 38 = 3

x_{1, 2} = \frac{- ( - 35 ) \pm 3}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 35 ) + 3}{2 \cdot 8}, x_{2} = \frac{- ( - 35 ) - 3}{2 \cdot 8}

x = \frac{- ( - 35 ) + 3}{2 \cdot 8} : \frac{19}{8}

x = \frac{- ( - 35 ) - 3}{2 \cdot 8} : 2

The solutions to the quadratic equation are:

x = \frac{19}{8}, x = 2

200 = t (18 - 0.2 t)

∣ 3 x - 2 ∣ = 5

2 x^{2} + 15 x + 18

∣ 7 x - 1 ∣ = 10

x^{2} + 4 x + 8

What are the solutions to the equation 8x^2-35x+38=0 ?
The solutions to the equation 8x^2-35x+38=0 are x= 19/8 ,x=2
Find the zeros of 8x^2-35x+38=0
The zeros of 8x^2-35x+38=0 are x= 19/8 ,x=2