What are the solutions to the equation g(g(3))=(3-2)-2 ?

The solutions to the equation g(g(3))=(3-2)-2 are g= 1/(sqrt(3))i,g=-1/(sqrt(3))i

Find the zeros of g(g(3))=(3-2)-2

The zeros of g(g(3))=(3-2)-2 are g= 1/(sqrt(3))i,g=-1/(sqrt(3))i

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g (g (3)) = (3 - 2) - 2

g = \frac{1}{3} i, g = - \frac{1}{3} i

Solution steps

g (g (3)) = (3 - 2) - 2

Simplify

3 g^{2} = - 1

Divide both sides by

3

\frac{3 g ^{2}}{3} = \frac{- 1}{3}

g^{2} = - \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

g = - \frac{1}{3}, g = - - \frac{1}{3}

- \frac{1}{3} = \frac{1}{3} i

- - \frac{1}{3} = - \frac{1}{3} i

g = \frac{1}{3} i, g = - \frac{1}{3} i

8!

1.2 x^{2} + x = 0

x^{2} = 6 x - 5

x^{2} - 2 x + 5 \leq 0

5 x^{2} - 125 = 0

What are the solutions to the equation g(g(3))=(3-2)-2 ?
The solutions to the equation g(g(3))=(3-2)-2 are g= 1/(sqrt(3))i,g=-1/(sqrt(3))i
Find the zeros of g(g(3))=(3-2)-2
The zeros of g(g(3))=(3-2)-2 are g= 1/(sqrt(3))i,g=-1/(sqrt(3))i