What are the solutions to the equation -v^2+9=0 ?

The solutions to the equation -v^2+9=0 are v=3,v=-3

Find the zeros of -v^2+9=0

The zeros of -v^2+9=0 are v=3,v=-3

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- v^{2} + 9 = 0

v = 3, v = - 3

Solution steps

- v^{2} + 9 = 0

Move

9

to the right side

- v^{2} = - 9

Divide both sides by

- 1

v^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 9, v = - 9

9 = 3

- 9 = - 3

v = 3, v = - 3

x^{2} - 2 x + 1 = 2

\frac{1 + 2 i}{3 - 4 i} + \frac{2 - i}{5 i}

f = 10 (60 - 65) + 50

26 = 6 x - 4

(x + 1)^{2} = 3 x + 7

What are the solutions to the equation -v^2+9=0 ?
The solutions to the equation -v^2+9=0 are v=3,v=-3
Find the zeros of -v^2+9=0
The zeros of -v^2+9=0 are v=3,v=-3