What are the solutions to the equation 8+5b-2b^2=9 ?

The solutions to the equation 8+5b-2b^2=9 are b=(5-sqrt(17))/4 ,b=(5+sqrt(17))/4

Find the zeros of 8+5b-2b^2=9

The zeros of 8+5b-2b^2=9 are b=(5-sqrt(17))/4 ,b=(5+sqrt(17))/4

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8 + 5 b - 2 b^{2} = 9

b = \frac{5 - 17}{4}, b = \frac{5 + 17}{4}

Decimal Notation

b = 0.21922 \dots, b = 2.28077 \dots

Solution steps

8 + 5 b - 2 b^{2} = 9

Move

9

to the left side

- 2 b^{2} + 5 b - 1 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

5^{2} - 4 (- 2) (- 1) = 17

b_{1, 2} = \frac{- 5 \pm 17}{2 ( - 2 )}

Separate the solutions

b_{1} = \frac{- 5 + 17}{2 ( - 2 )}, b_{2} = \frac{- 5 - 17}{2 ( - 2 )}

b = \frac{- 5 + 17}{2 ( - 2 )} : \frac{5 - 17}{4}

b = \frac{- 5 - 17}{2 ( - 2 )} : \frac{5 + 17}{4}

The solutions to the quadratic equation are:

b = \frac{5 - 17}{4}, b = \frac{5 + 17}{4}

x^{2} - 3 x \leq 40

5 - 2 ∣ 3 - 2 x ∣ \leq 1

- 7 = s + (- 13)

2 5^{\frac{1}{2}} (x^{2})^{\frac{1}{2}}

n^{2} - 2 n - 48

What are the solutions to the equation 8+5b-2b^2=9 ?
The solutions to the equation 8+5b-2b^2=9 are b=(5-sqrt(17))/4 ,b=(5+sqrt(17))/4
Find the zeros of 8+5b-2b^2=9
The zeros of 8+5b-2b^2=9 are b=(5-sqrt(17))/4 ,b=(5+sqrt(17))/4