What are the solutions to the equation (z+3)(z-7)=0 ?

The solutions to the equation (z+3)(z-7)=0 are z=-3,z=7

Find the zeros of (z+3)(z-7)=0

The zeros of (z+3)(z-7)=0 are z=-3,z=7

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(z + 3) (z - 7) = 0

z = - 3, z = 7

Solution steps

(z + 3) (z - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

z + 3 = 0 or z - 7 = 0

Solve

z + 3 = 0 : z = - 3

Solve

z - 7 = 0 : z = 7

The solutions to the quadratic equation are:

z = - 3, z = 7

2 x^{2} - 7 x = - 3

- \frac{4}{3} + 2

- 3 x \leq 6

- 2 x - 10 \leq 6

\frac{5 \cdot 180}{12}

What are the solutions to the equation (z+3)(z-7)=0 ?
The solutions to the equation (z+3)(z-7)=0 are z=-3,z=7
Find the zeros of (z+3)(z-7)=0
The zeros of (z+3)(z-7)=0 are z=-3,z=7