What are the solutions to the equation m^2+8m=0 ?

The solutions to the equation m^2+8m=0 are m=0,m=-8

Find the zeros of m^2+8m=0

The zeros of m^2+8m=0 are m=0,m=-8

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m^{2} + 8 m = 0

m = 0, m = - 8

Solution steps

m^{2} + 8 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

m_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 8}{2 \cdot 1}, m_{2} = \frac{- 8 - 8}{2 \cdot 1}

m = \frac{- 8 + 8}{2 \cdot 1} : 0

m = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

m = 0, m = - 8

3 (h - 2) + 1 = - h + 4 + 5 h

4 x^{2} + 16 x + 17 = 0

x^{4} - 15 x^{2} - 16

\frac{2}{3} + \frac{3}{4}

(\frac{1}{3})^{\frac{2}{3}}

What are the solutions to the equation m^2+8m=0 ?
The solutions to the equation m^2+8m=0 are m=0,m=-8
Find the zeros of m^2+8m=0
The zeros of m^2+8m=0 are m=0,m=-8