What is \sqrt[3]{-8x^{-3}y^9} ?

The solution to \sqrt[3]{-8x^{-3}y^9} is -(2y^3)/x

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simplify \sqrt[3]{-8x^{-3}y^9}

simplify

- \frac{2 y ^{3}}{x}

Solution steps

Simplify

Remove parentheses:

Simplify

= - 2 y^{3} \frac{1}{x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{2 y ^{3} \cdot 1}{x}

Multiply the numbers:

2 \cdot 1 = 2

= - \frac{2 y ^{3}}{x}

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What is \sqrt[3]{-8x^{-3}y^9} ?
The solution to \sqrt[3]{-8x^{-3}y^9} is -(2y^3)/x