What are the solutions to the equation 0=-20x^2+1900x-31000 ?

The solutions to the equation 0=-20x^2+1900x-31000 are x=(5(19-sqrt(113)))/2 ,x=(5(19+sqrt(113)))/2

Find the zeros of 0=-20x^2+1900x-31000

The zeros of 0=-20x^2+1900x-31000 are x=(5(19-sqrt(113)))/2 ,x=(5(19+sqrt(113)))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 20 x^{2} + 1900 x - 31000

x = \frac{5 ( 19 - 113 )}{2}, x = \frac{5 ( 19 + 113 )}{2}

Decimal Notation

x = 20.92463 \dots, x = 74.07536 \dots

Solution steps

0 = - 20 x^{2} + 1900 x - 31000

Switch sides

- 20 x^{2} + 1900 x - 31000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1900 \pm 190 0 ^{2} - 4 ( - 20 ) ( - 31000 )}{2 ( - 20 )}

190 0^{2} - 4 (- 20) (- 31000) = 100113

x_{1, 2} = \frac{- 1900 \pm 100 113}{2 ( - 20 )}

Separate the solutions

x_{1} = \frac{- 1900 + 100 113}{2 ( - 20 )}, x_{2} = \frac{- 1900 - 100 113}{2 ( - 20 )}

x = \frac{- 1900 + 100 113}{2 ( - 20 )} : \frac{5 ( 19 - 113 )}{2}

x = \frac{- 1900 - 100 113}{2 ( - 20 )} : \frac{5 ( 19 + 113 )}{2}

The solutions to the quadratic equation are:

x = \frac{5 ( 19 - 113 )}{2}, x = \frac{5 ( 19 + 113 )}{2}

3 x^{2} = 12 x - 12

x - 3 = 10

4 (x - 1) - 15 = 3 (x - 1)

\frac{2}{3} - \frac{1}{2}

What are the solutions to the equation 0=-20x^2+1900x-31000 ?
The solutions to the equation 0=-20x^2+1900x-31000 are x=(5(19-sqrt(113)))/2 ,x=(5(19+sqrt(113)))/2
Find the zeros of 0=-20x^2+1900x-31000
The zeros of 0=-20x^2+1900x-31000 are x=(5(19-sqrt(113)))/2 ,x=(5(19+sqrt(113)))/2