What are the solutions to the equation x^2+7x=60 ?

The solutions to the equation x^2+7x=60 are x=5,x=-12

Find the zeros of x^2+7x=60

The zeros of x^2+7x=60 are x=5,x=-12

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x^{2} + 7 x = 60

x = 5, x = - 12

Solution steps

x^{2} + 7 x = 60

Move

60

to the left side

x^{2} + 7 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 60) = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 1}, x_{2} = \frac{- 7 - 17}{2 \cdot 1}

x = \frac{- 7 + 17}{2 \cdot 1} : 5

x = \frac{- 7 - 17}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 5, x = - 12

- 8 - 14

42 = y + 15

(x^{2} - 4 x) (3 x + 2)^{3} + 4 (3 x + 2)^{3}

8 x^{2} + 14 x - 15 = 0

y^{4} - 16

What are the solutions to the equation x^2+7x=60 ?
The solutions to the equation x^2+7x=60 are x=5,x=-12
Find the zeros of x^2+7x=60
The zeros of x^2+7x=60 are x=5,x=-12