What are the solutions to the equation 6x^2+11x+4=0 ?

The solutions to the equation 6x^2+11x+4=0 are x=-1/2 ,x=-4/3

Find the zeros of 6x^2+11x+4=0

The zeros of 6x^2+11x+4=0 are x=-1/2 ,x=-4/3

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6 x^{2} + 11 x + 4 = 0

x = - \frac{1}{2}, x = - \frac{4}{3}

Decimal Notation

x = - 0.5, x = - 1.33333 \dots

Solution steps

6 x^{2} + 11 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

1 1^{2} - 4 \cdot 6 \cdot 4 = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 \cdot 6}, x_{2} = \frac{- 11 - 5}{2 \cdot 6}

x = \frac{- 11 + 5}{2 \cdot 6} : - \frac{1}{2}

x = \frac{- 11 - 5}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{4}{3}

4 \cdot \frac{5}{7}

4 x^{2} + 7 = 15

n^{2} + 2 n - 48

\frac{3}{4} (2)^{3}

∣ x - 1 ∣ + ∣ x + 1 ∣ > 2

What are the solutions to the equation 6x^2+11x+4=0 ?
The solutions to the equation 6x^2+11x+4=0 are x=-1/2 ,x=-4/3
Find the zeros of 6x^2+11x+4=0
The zeros of 6x^2+11x+4=0 are x=-1/2 ,x=-4/3