What are the solutions to the equation 7^2+b^2=10^2 ?

The solutions to the equation 7^2+b^2=10^2 are b=sqrt(51),b=-sqrt(51)

Find the zeros of 7^2+b^2=10^2

The zeros of 7^2+b^2=10^2 are b=sqrt(51),b=-sqrt(51)

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7^{2} + b^{2} = 1 0^{2}

b = 51, b = - 51

Decimal Notation

b = 7.14142 \dots, b = - 7.14142 \dots

Solution steps

7^{2} + b^{2} = 1 0^{2}

Move

7^{2}

to the right side

b^{2} = 51

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 51, b = - 51

x - 1.4 = 0.6

4 x^{2} + 36 x y + 81 y^{2}

z^{2} + z + 25 = 0

\frac{( \frac{3}{2} )}{\frac{1}{2}}

2 y^{2} - y - 15

What are the solutions to the equation 7^2+b^2=10^2 ?
The solutions to the equation 7^2+b^2=10^2 are b=sqrt(51),b=-sqrt(51)
Find the zeros of 7^2+b^2=10^2
The zeros of 7^2+b^2=10^2 are b=sqrt(51),b=-sqrt(51)