What is (1/6+1/3*sqrt(-x^6+x^4))>0 ?

The solution to (1/6+1/3*sqrt(-x^6+x^4))>0 is -1<= x<= 1

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(1/6+1/3*sqrt(-x^6+x^4))>0

(\frac{1}{6} + \frac{1}{3} \cdot - x^{6} + x^{4}) > 0

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

\frac{1}{6} + \frac{1}{3} - x^{6} + x^{4} > 0

Move

\frac{1}{6}

to the right side

\frac{1}{3} - x^{6} + x^{4} > - \frac{1}{6}

Multiply both sides by

3

- x^{6} + x^{4} > - \frac{1}{2}

If n is even,

for all

u

True for all x

Find singularity points

Find non-negative values for radicals:

- 1 \leq x \leq 1

Combine the intervals

True for all x and - 1 \leq x \leq 1

Merge Overlapping Intervals

- 1 \leq x \leq 1

10 = 490 t^{2}

1 + 8 w = 10 - w

x^{4} - 4 x^{3} + 3 x^{2} - 16 x^{2} + 64 x - 48

What is (1/6+1/3*sqrt(-x^6+x^4))>0 ?
The solution to (1/6+1/3*sqrt(-x^6+x^4))>0 is -1<= x<= 1