What is the domain of f(n)=(n^3-n)/(n^2-5n-6) ?

The domain of f(n)=(n^3-n)/(n^2-5n-6) is n 6

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domain of f(n)=(n^3-n)/(n^2-5n-6)

domain

f (n) = \frac{n ^{3} - n}{n ^{2} - 5 n - 6}

n < - 1 or - 1 < n < 6 or n > 6

Interval Notation

(- \infty, - 1) \cup (- 1, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

n = 6, n = - 1

The function domain

n < - 1 or - 1 < n < 6 or n > 6

\frac{5}{3} + (- \frac{7}{6})

\frac{3}{5} x + \frac{4}{5} = - \frac{2}{5}

8 x^{2} + 26 x - 7

- 3 ∣ 3 - 4 x ∣ + 9 = 8

- 2 - \frac{1}{4}

What is the domain of f(n)=(n^3-n)/(n^2-5n-6) ?
The domain of f(n)=(n^3-n)/(n^2-5n-6) is n<-1\lor-1<n<6\lor n>6