What are the solutions to the equation x^2+8x-3=-2x-3 ?

The solutions to the equation x^2+8x-3=-2x-3 are x=0,x=-10

Find the zeros of x^2+8x-3=-2x-3

The zeros of x^2+8x-3=-2x-3 are x=0,x=-10

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x^{2} + 8 x - 3 = - 2 x - 3

x = 0, x = - 10

Solution steps

x^{2} + 8 x - 3 = - 2 x - 3

Move

3

to the left side

x^{2} + 8 x = - 2 x

Move

2 x

to the left side

x^{2} + 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 0 = 10

x_{1, 2} = \frac{- 10 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 10}{2 \cdot 1}, x_{2} = \frac{- 10 - 10}{2 \cdot 1}

x = \frac{- 10 + 10}{2 \cdot 1} : 0

x = \frac{- 10 - 10}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 0, x = - 10

\frac{1}{\frac{1}{6}}

\frac{2 - \frac{3}{4}}{\frac{1}{2} - \frac{1}{3}}

12 x^{2} - 10 x - 6 = 11

- 7 - 11

\frac{3 x}{5} + 3 = 7

What are the solutions to the equation x^2+8x-3=-2x-3 ?
The solutions to the equation x^2+8x-3=-2x-3 are x=0,x=-10
Find the zeros of x^2+8x-3=-2x-3
The zeros of x^2+8x-3=-2x-3 are x=0,x=-10