What are the solutions to the equation x^2-4x+10=0 ?

The solutions to the equation x^2-4x+10=0 are x=2+sqrt(6)i,x=2-sqrt(6)i

Find the zeros of x^2-4x+10=0

The zeros of x^2-4x+10=0 are x=2+sqrt(6)i,x=2-sqrt(6)i

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x^{2} - 4 x + 10 = 0

x = 2 + 6 i, x = 2 - 6 i

Solution steps

x^{2} - 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 10 : 26 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 1} : 2 + 6 i

x = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 1} : 2 - 6 i

The solutions to the quadratic equation are:

x = 2 + 6 i, x = 2 - 6 i

3 (2 x - 3) + 2 (2 x - 2) + 10 = 5 x + 17

y, \frac{l y l}{2} = 28

x^{3} + 7 x^{2} - 7 x - 49

4 r - 4 \leq 10 r - 10 \leq 10 + 5 r

\frac{1}{8} \cdot 8

What are the solutions to the equation x^2-4x+10=0 ?
The solutions to the equation x^2-4x+10=0 are x=2+sqrt(6)i,x=2-sqrt(6)i
Find the zeros of x^2-4x+10=0
The zeros of x^2-4x+10=0 are x=2+sqrt(6)i,x=2-sqrt(6)i