What are the solutions to the equation 3k^2-6k-9=0 ?

The solutions to the equation 3k^2-6k-9=0 are k=3,k=-1

Find the zeros of 3k^2-6k-9=0

The zeros of 3k^2-6k-9=0 are k=3,k=-1

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3 k^{2} - 6 k - 9 = 0

k = 3, k = - 1

Solution steps

3 k^{2} - 6 k - 9 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 9) = 12

k_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 \cdot 3}

Separate the solutions

k_{1} = \frac{- ( - 6 ) + 12}{2 \cdot 3}, k_{2} = \frac{- ( - 6 ) - 12}{2 \cdot 3}

k = \frac{- ( - 6 ) + 12}{2 \cdot 3} : 3

k = \frac{- ( - 6 ) - 12}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

k = 3, k = - 1

1 \leq y

16 x^{6} y + 16 x^{2} y^{4} + 32 x^{3} y^{2}

\frac{3}{2} c + 23 = 38

4 y - 3 = 2 y + 3

x^{2} - 4 2^{2}

What are the solutions to the equation 3k^2-6k-9=0 ?
The solutions to the equation 3k^2-6k-9=0 are k=3,k=-1
Find the zeros of 3k^2-6k-9=0
The zeros of 3k^2-6k-9=0 are k=3,k=-1