What are the solutions to the equation 1/2 x^2-2x+3/2 =0 ?

The solutions to the equation 1/2 x^2-2x+3/2 =0 are x=3,x=1

Find the zeros of 1/2 x^2-2x+3/2 =0

The zeros of 1/2 x^2-2x+3/2 =0 are x=3,x=1

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\frac{1}{2} x^{2} - 2 x + \frac{3}{2} = 0

x = 3, x = 1

Solution steps

\frac{1}{2} x^{2} - 2 x + \frac{3}{2} = 0

Multiply both sides by

2

x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

x = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

6^{0}

- 2 x + 6 \geq 16

7 mn + 14 m + 4 n + 8

- 1 \leq \frac{v - 2}{21}

27 - 8 u^{3}

What are the solutions to the equation 1/2 x^2-2x+3/2 =0 ?
The solutions to the equation 1/2 x^2-2x+3/2 =0 are x=3,x=1
Find the zeros of 1/2 x^2-2x+3/2 =0
The zeros of 1/2 x^2-2x+3/2 =0 are x=3,x=1