What is the answer to 6(9y-1)-10(5y)-3y=22-4(2y-12)+8(y-6) ?

The answer to 6(9y-1)-10(5y)-3y=22-4(2y-12)+8(y-6) is y=28

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6(9y-1)-10(5y)-3y=22-4(2y-12)+8(y-6)

6 (9 y - 1) - 10 (5 y) - 3 y = 22 - 4 (2 y - 12) + 8 (y - 6)

y = 28

Solution steps

6 (9 y - 1) - 10 (5 y) - 3 y = 22 - 4 (2 y - 12) + 8 (y - 6)

Remove parentheses:

(a) = a

6 (9 y - 1) - 10 \cdot 5 y - 3 y = 22 - 4 (2 y - 12) + 8 (y - 6)

Multiply the numbers:

10 \cdot 5 = 50

6 (9 y - 1) - 50 y - 3 y = 22 - 4 (2 y - 12) + 8 (y - 6)

Add similar elements:

- 50 y - 3 y = - 53 y

6 (9 y - 1) - 53 y = 22 - 4 (2 y - 12) + 8 (y - 6)

Expand

6 (9 y - 1) - 53 y : y - 6

Expand

22 - 4 (2 y - 12) + 8 (y - 6) : 22

y - 6 = 22

Move

6

to the right side

y = 28

- 11 x - 17 x + 31 x = 15 - 36

18 b > - 24

4 - \frac{x}{5} > 7

0 = x^{2} - 6 x + 5

2 x + 8 = 6 x - 28

What is the answer to 6(9y-1)-10(5y)-3y=22-4(2y-12)+8(y-6) ?
The answer to 6(9y-1)-10(5y)-3y=22-4(2y-12)+8(y-6) is y=28
Solve for y: 6(9y-1)-10(5y)-3y=22-4(2y-12)+8(y-6)
The solution is y=28