What are the solutions to the equation -3x^2+11=17 ?

The solutions to the equation -3x^2+11=17 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of -3x^2+11=17

The zeros of -3x^2+11=17 are x=sqrt(2)i,x=-sqrt(2)i

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- 3 x^{2} + 11 = 17

x = 2 i, x = - 2 i

Solution steps

- 3 x^{2} + 11 = 17

Move

11

to the right side

- 3 x^{2} = 6

Divide both sides by

- 3

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

(\frac{1}{20})^{4}

(3 x^{2} + 2 x y + 7) - (6 x^{2} - 4 x y + 3)

8 x^{2} = 64

(2 y - 5) - 8 = (3 - y) + 2

4 a^{2} + 4 a - 80

What are the solutions to the equation -3x^2+11=17 ?
The solutions to the equation -3x^2+11=17 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of -3x^2+11=17
The zeros of -3x^2+11=17 are x=sqrt(2)i,x=-sqrt(2)i