What are the solutions to the equation r^2-20r+100=0 ?

The solutions to the equation r^2-20r+100=0 are r=10

Find the zeros of r^2-20r+100=0

The zeros of r^2-20r+100=0 are r=10

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r^{2} - 20 r + 100 = 0

r = 10

Solution steps

r^{2} - 20 r + 100 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 100 = 0

r_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 1}

r = \frac{- ( - 20 )}{2 \cdot 1}

\frac{- ( - 20 )}{2 \cdot 1} = 10

r = 10

The solution to the quadratic equation is:

r = 10

\frac{3}{4} - 10

x^{2} - 3 x - 10

18 a^{2} + 10 a = - 11 a + 4

lo g_{5} (- 25)

x^{2} + 18 x + 70 = 0

What are the solutions to the equation r^2-20r+100=0 ?
The solutions to the equation r^2-20r+100=0 are r=10
Find the zeros of r^2-20r+100=0
The zeros of r^2-20r+100=0 are r=10