What are the solutions to the equation x^2=-20x-99 ?

The solutions to the equation x^2=-20x-99 are x=-9,x=-11

Find the zeros of x^2=-20x-99

The zeros of x^2=-20x-99 are x=-9,x=-11

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x^{2} = - 20 x - 99

x = - 9, x = - 11

Solution steps

x^{2} = - 20 x - 99

Move

99

to the left side

x^{2} + 99 = - 20 x

Move

20 x

to the left side

x^{2} + 99 + 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 20 x + 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 99}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 99 = 2

x_{1, 2} = \frac{- 20 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 2}{2 \cdot 1}, x_{2} = \frac{- 20 - 2}{2 \cdot 1}

x = \frac{- 20 + 2}{2 \cdot 1} : - 9

x = \frac{- 20 - 2}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 9, x = - 11

x^{2} + 7 x y + 6 y^{2}

30 b^{5}

\frac{16 x y ^{4}}{24 x ^{4} y ^{8}}

400 + 441

5 \leq x - 6 < 11

What are the solutions to the equation x^2=-20x-99 ?
The solutions to the equation x^2=-20x-99 are x=-9,x=-11
Find the zeros of x^2=-20x-99
The zeros of x^2=-20x-99 are x=-9,x=-11