What is (3x-5)/(x+1)>= 1/3 ?

The solution to (3x-5)/(x+1)>= 1/3 is x = 2

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(3x-5)/(x+1)>= 1/3

\frac{3 x - 5}{x + 1} \geq \frac{1}{3}

x < - 1 or x \geq 2

Interval Notation

(- \infty, - 1) \cup [2, \infty)

Solution steps

\frac{3 x - 5}{x + 1} \geq \frac{1}{3}

Rewrite in standard form

\frac{8 x - 16}{x + 1} \geq 0

Factor

\frac{8 x - 16}{x + 1} : \frac{8 ( x - 2 )}{x + 1}

\frac{8 ( x - 2 )}{x + 1} \geq 0

Divide both sides by

8

\frac{\frac{8 ( x - 2 )}{x + 1}}{8} \geq \frac{0}{8}

Simplify

\frac{x - 2}{x + 1} \geq 0

Identify the intervals

x < - 1 or x \geq 2

\frac{4 !}{2 ! ( 4 - 2 ) !}

9 n^{6} - 6561 n^{3}

10 x^{3} + 27 x^{2} + 20 x + 3 > 0

lo g_{1} (5)

5 ((7 n + 1)) \geq - 205

What is (3x-5)/(x+1)>= 1/3 ?
The solution to (3x-5)/(x+1)>= 1/3 is x<-1\lor x>= 2